1948 United States presidential election in Utah

1948 United States presidential election in Utah
Truman 50–60% 60–70%	Dewey 50-60% 70-80%
President before election; Harry S. Truman; Democratic	Elected President ; Harry S. Truman; Democratic

The 1948 United States presidential election in Utah was held on November 2, 1948 as part of the 1948 United States presidential election. State voters chose four electors to the Electoral College, who voted for president and vice president.

Utah was won by Democratic Party candidate Harry S. Truman, who carried the state with 53.98 percent of the popular vote and winning its four electoral votes.^[1] As of the 2020 presidential election^[update], this is the last election in which Davis County and Uintah County voted for a Democratic presidential candidate.^[2]

This was the last election in which Utah voted more Democratic than the nation. After 1948, the state would shift strongly toward the Republican Party, only backing the Democratic presidential nominee once more, during Lyndon B. Johnson's 1964 landslide, and in many election cycles afterward being the most Republican state in the nation. As of 2020 this is also the last time that Utah voted more Democratic than Illinois.

^ "1948 Presidential General Election Results - Utah". Retrieved October 19, 2017.
^ Sullivan, Robert David; ‘How the Red and Blue Map Evolved Over the Past Century’; America Magazine in The National Catholic Review; June 29, 2016

[1] "1948 Presidential General Election Results - Utah". Retrieved October 19, 2017.

[how-2] Sullivan, Robert David; ‘How the Red and Blue Map Evolved Over the Past Century’; America Magazine in The National Catholic Review; June 29, 2016

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